► Last two digits of 76^n are 76 (where n is a natural number).
► If last two digits of ab^n = ab then ab = 00, 01, 25 or 76.
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In your examination, you might get a question :
Find the last two digits of 2345678765676^76876545434^5467876^876567 .
Ans is 76 (since last two digits of base is 76, hardly 2 sec.)
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